2p^2+20p=6000

Solution for 2p^2+20p=6000 equation:

2p^2+20p=6000

We move all terms to the left:

2p^2+20p-(6000)=0

a = 2; b = 20; c = -6000;
Δ = b2-4ac
Δ = 202-4·2·(-6000)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-220}{2*2}=\frac{-240}{4}
=-60
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+220}{2*2}=\frac{200}{4}
=50
$